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 Rank: Top Rank Aluminum Star Groups: Member
Joined: 10/17/2008 Posts: 208 Points: 148 Location: Gainesboro, TN
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Dougrose - I found(thru search), where you wrote: Each battery is connected to the solar cells through two diodes, forward biased, that provide about 0.6 volt drop each. Since almost 19 volts are available, this does not reduce charging current. One of the two diodes is paralleled by a 1 ohm 1 watt resistor. This arrangement gives each battery some charge even though the voltages may be somewhat different, and puts all of the charging capacity toward one battery if it is really low. Would you look or do you remember whether the band/cathode was toward the solar panel, or the battery? I'm trying to straighten my mind out about something I read about what actually goes on during charging. What I read, was that the charger takes electrons away from the positive plates, rather than putting them in and the direction of your diodes will tell us whether this is true or not(since they tell me electron flow is against the arrow in the symbol)?? Thanks,
Jim  Defeated Creek Marina Cordell Hull Lake, Tennessee
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 Rank: Top Rank Aluminum Star Groups: Member
Joined: 12/7/2007 Posts: 916 Points: 1,087 Location: Central Florida and the DC area
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Jim, I am sorry that I cannot refer you to my website, since I don't have one anymore - new one is in work. I have extracted a file in png whatever that is and will try to post it here. It shows the charging system that I am currently using 
"Anyone who has ever chanted "drill, baby, drill" please report to the bayou for cleanup duty..."
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 Rank: Top Rank Aluminum Star Groups: Member
Joined: 10/17/2008 Posts: 208 Points: 148 Location: Gainesboro, TN
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Thank you for the diagram. If I read it right, then what I read earlier about charging is correct. All these years, I thought we were putting something INTO the battery rather than taking something OUT. I suppose this action goes on until chemical action within the battery ceases....?
Jim  Defeated Creek Marina Cordell Hull Lake, Tennessee
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 Rank: Top Rank Aluminum Star Groups: Member
Joined: 12/7/2007 Posts: 916 Points: 1,087 Location: Central Florida and the DC area
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Don't forget that conventional current flows in the direction of the diode "arrow", from + to - . This is the opposite direction from the actual flow of electrons - they flow from - to + . This works out mathematically because electrons carry a negative charge, so when they are flowing to the right, the conventional current, which is positive, is flowing to the left.
I think it was Ben Franklin who made the mistake originally, or maybe someone else. At any rate, when you discharge a battery, the electrons are flowing from the - to the + . When you charge it, they are going the other way.
That's what happens when you define the direction of current before you know what it is made of. Had a 50-50 shot to get it right and blew it.
"Anyone who has ever chanted "drill, baby, drill" please report to the bayou for cleanup duty..."
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 Rank: Top Rank Aluminum Star Groups: Member
Joined: 10/17/2008 Posts: 208 Points: 148 Location: Gainesboro, TN
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Isn't current defined as the flow of electrons past a given point - or something to that effect. I gotta go look it up again....
Jim  Defeated Creek Marina Cordell Hull Lake, Tennessee
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 Rank: Top Rank Aluminum Star Groups: Member
Joined: 12/7/2007 Posts: 916 Points: 1,087 Location: Central Florida and the DC area
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Yup. The unit of electric charge is the coulomb. each colomb has something like 6.24 X 10^18 electrons in it. If one coulomb flows past your given point in one second, then the current is one ampere.
"Anyone who has ever chanted "drill, baby, drill" please report to the bayou for cleanup duty..."
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 Rank: Top Rank Aluminum Star Groups: Member
Joined: 10/17/2008 Posts: 208 Points: 148 Location: Gainesboro, TN
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Thanks for your time in replying, Dougrose.
Jim  Defeated Creek Marina Cordell Hull Lake, Tennessee
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